This Sudoku TRICK Can Quickly Solve Very Hard Puzzles

Join the Smartie Party now 🥳to get EXCLUSIVE reward puzzle packs, ad free content, discord access, and so much more👉👉www.buymeacoffee.com/timberlakeB/membership Timestamps 0:00 Intro 00:26 It’s Solving Time 01:27 Spotting Claiming Pairs 02:19 Puzzle Story 03:55 Hidden Single Tip 05:05 Naked Pair 06:44 BONUS Tip 07:31 Shout Out #1 07:48 Critical Solving Steps 09:03 What To Do After Snyder 09:58 Shout Out #2 10:35 Trick Revealed 13:32 Solving The Green Cell 14:07 Following The Snyder 15:47 Sweeping The Blo

Found it easy as I know the w- wing D variant strategy.

I found another superfluous finned X-wing in 8s, but I also found something -- maybe the intended trick -- in the top band, that placed 6 in the green cell. R3C1 was either 6 or 8. If 6, it forced a 18 pair in block 3 which removed row 2 8s from block 1. If 8, row 2 8s couldn't exist in block 1. Henced they were removed. That led to a 67 pair in column 8, block 3, and placed 6 in the green cell. Things went smoothly afterwards. 0:10 The clock was running? I would never have beat that. 13:10 Mine wasn't the two-string kite or the W-delta. But I guess it was equivalent -- removing row 2 8s from block 1, leaving them in block 3 and forcing the 67 pair in column 8.

Great puzzle, very difficult indeed for a championship game. Stuck to notation free, keeping the main bi-value cells in mind. With the 367 triple in row 1, I was indeed able to figure out that if the 7 was in r1c8 and ib r3c3, and hence the 6 up in row 1 in block1, thence in r2c3 and r3c8. Now that I have the 67 pair in col 8 in block 3, the puzzle becomes easy again. Neat. Thanks for explaining so well what my crude technique was :)

Wow! How did we suddenly arrive at such a leap in difficulty? I used a two-way chain to break this (16 = row 1 column 6): 16, 17, 32, 61, 55, 14, 34, 39, 74, 85, 36, 75, 41, 19 (hidden single), 25 (two-way chain on 6s from box 1)*, 35, 97, 31, 38, 12, 71, 79, 87, 93, 82, 72, 88, 98, 81, 83, 78, 89, 76, 91, 92, 21, 25, 13, 23, 18, 58, 63, 43, 53, 57, 29, 27, 69, 49, 47, 67, 44, 46, 94, 96, 64, 66. * R3C1 = 6 → R2C5 = 6; R1C2 = 6 → R2C3 = 7 → R3C5 = 7 → R2C5 = 6. This puzzle reminded me of the very first Sudoku I created (way back in 2019, or thereabouts). To this day, it remains one of the prettiest I've done. I can't find it now, but I think I may have recreated it, or something very similar: 900 030 000 000 204 030 001 000 500 020 100 060 300 000 007 040 009 080 005 000 900 070 608 000 000 070 001 900030000000204030001000500020100060300000007040009080005000900070608000000070001 HoDoKu rating: Medium 746 (Extreme 5460 without R8C2). Andrew Stuart rating: Tough Grade 105 (Extreme Grade 831 without R8C2). Afterthought: I loved your breakthrough. Mine was rather unconventional, and was probably Sudoku heresy. Edited to correct a wrong date.

Jellyfish on 6’s, columns 1,2,5 and 8, rules out a 6 in column 7 row 2(r2c7)… well I’m not certain if jellyfish principle is properly applied but, after observing a symmetry of the puzzle I somehow knew a ‘fish’ of some sort should apply. 6 was chosen because how it behaved in box 4, making eliminations in column 3( box 1 and box 7)… 😅😅😅 I found a solution, but not certain if it was intended solve😢😢

at 8:54, how did you eliminate placing candidate 9s in box 7, column 3 and only place them in column 1?

Yikes, I took a pounding on this one, 49:17. And that doesn't count the time I had to look at the video. This puzzle depended upon filling in the right cells, and I just didn't have the right cells filled in to find the Delta Variant.